1、采用 Array(str)、String(array) 方法
String转Character数组:Array(str) Character数组转String:String(array)
let test = "i like ios"
let array = Array(test) //[Character]
let string = String(array) //String
print(array)
print(string)
结果打印:
[“i”, " ", “l”, “i”, “k”, “e”, " ", “i”, “o”, “s”] i like ios
2、采用String.components(separatedBy: " ")、[String].joined(separator: " ")
String转[String]数组:String.components(separatedBy: " ") [String]数组转String:[String].joined(separator: " ")
let test = "i like ios"
let array = test.components(separatedBy: " ")
let intArray = [1,2,3,4,5]
let dataArray = intArray.map(String.init)
let resultString = dataArray.joined(separator: "")
print(array)
print(resultString)
结果打印:
[“i”, “like”, “ios”] 12345
3、采用String.index(吐槽一下:这api真不好用)
String获取指定index的Character:String[String.index] String根据index区间获取SubString:String(String[index_1...index_2])
let test = "i like ios"
let char_0 = test[test.index(test.startIndex, offsetBy: 0)]
let char_8 = test[test.index(test.startIndex, offsetBy: 8)]
let beginIndex = test.index(test.startIndex, offsetBy: 0)
let endIndex = test.index(test.startIndex, offsetBy: 8)
let subString = String(test[beginIndex...endIndex])
print(char_0)
print(char_8)
print(subString)
结果打印:
i o i like io
tips:
swift里的字符、字符串处理api比较多,在此记录几个经常使用的swift字符相关处理技巧
let charOfA = Character("A")
let uInt8Value = charOfA.asciiValue! //Character转UInt8
let char = Character(UnicodeScalar(uInt8Value)) //UInt8转Character
let intArray = [1,2,3,4,5,6]
let strArray = intArray.map(String.init) //[Int]转[String]
let str_Array = ["123","01","xx","000"]
let int_Array = str_Array.map(Int.init) //[String]转[Int?] 因为有的字符串无法转int,该index存在且为nil
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